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Use single UI state for activity

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This commit is contained in:
Kirill Kamakin
2022-04-09 00:47:50 +05:00
parent 536c9765cb
commit e7620400b8
8 changed files with 56 additions and 45 deletions
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7
app/src/main/java/gq/kirmanak/mealient/ui/auth/AuthenticationFragment.kt
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@@ -2,8 +2,8 @@ package gq.kirmanak.mealient.ui.auth
import android.os.Bundle
import android.view.View
import androidx.appcompat.app.AppCompatActivity
import androidx.fragment.app.Fragment
import androidx.fragment.app.activityViewModels
import androidx.fragment.app.viewModels
import androidx.navigation.fragment.findNavController
import by.kirich1409.viewbindingdelegate.viewBinding
@@ -12,19 +12,20 @@ import gq.kirmanak.mealient.R
import gq.kirmanak.mealient.data.network.NetworkError
import gq.kirmanak.mealient.databinding.FragmentAuthenticationBinding
import gq.kirmanak.mealient.extensions.checkIfInputIsEmpty
import gq.kirmanak.mealient.ui.activity.MainActivityViewModel
import timber.log.Timber
@AndroidEntryPoint
class AuthenticationFragment : Fragment(R.layout.fragment_authentication) {
private val binding by viewBinding(FragmentAuthenticationBinding::bind)
private val viewModel by viewModels<AuthenticationViewModel>()
private val activityViewModel by activityViewModels<MainActivityViewModel>()
override fun onViewCreated(view: View, savedInstanceState: Bundle?) {
super.onViewCreated(view, savedInstanceState)
Timber.v("onViewCreated() called with: view = $view, savedInstanceState = $savedInstanceState")
binding.button.setOnClickListener { onLoginClicked() }
(requireActivity() as? AppCompatActivity)?.supportActionBar?.title =
getString(R.string.app_name)
activityViewModel.updateUiState { it.copy(loginButtonVisible = false, titleVisible = true) }
viewModel.authenticationResult.observe(viewLifecycleOwner, ::onAuthenticationResult)
}